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*Trigonometry and area*

Find the area of a regular pentagon with a side length of 8cm. Round to the nearest tenth

1 Answer

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Answer:

110.1 cm^2 to nearest tenth.

Step-by-step explanation:

The area consists of 5 isosceles triangles with base angles 1/2 * 108 = 54 degrees.

Using trigonometry to find the height of these triangles:

tan 54 = h / (1/2 * 8)

tan 54 = h / 4

h = 4 tan 54

h = 5.506 cm.

The area of a triangle = 4 * 5.506 = 22.024 cm^2

So the area of the pentagon 5 * 22.024

= 110.12 cm^2.

User Pravin Poudel
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