Question

Fastas soon as possible............Find HCF​

Answer 1

Step-by-step explanation:

Consider expression

Rewrite it:

Consider the numerator:

Use formula:

So,

Now,

Hence,

Answer:

Explanation:

Answer 2

`y^4+1+(1)/(y^4)`

Explanation:

Consider expression

`y^7-(1)/(y^5)`

Rewrite it:

`(y^7\cdot y^5-1)/(y^5)=(y^(12)-1)/(y^5)`

Consider the numerator:

`y^(12)-1=(y^4)^3-1^3`

Use formula:

`a^3-b^3=(a-b)(a^2+ab+b^2)`

So,

`(y^4)^3-1^3=(y^4-1)((y^4)^2+y^4\cdot 1+1^2)=(y^4-1)(y^8+y^4+1)`

Now,

`(y^7\cdot y^5-1)/(y^5)=((y^4-1)(y^8+y^4+1))/(y^5)=(y^4-1)/(y)\cdot \left(y^4+1+(1)/(y^4)\right)`

Hence,

`GCF(y^7-(1)/(y^5), y^4+1+(1)/(y^4))=y^4+1+(1)/(y^4)`