Question

What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?

answers y = -5x -16
y = -5x -8
y = -5x +8
y = -5x + 16

Answer 1

Answer: y=-5x-8

Let’s start by writing out the model equation for slope-intercept

y=mx+b

M: Slope
X: Variable
B: Y-intercept

Now we know that m is slope. Let’s fill in the slope provided to us, which is -5

y=mx+b

y=-5x+b

Now let’s solve for b. We’ll do this by taking the point given to us and substituting it into the equation and solving.

y=-5x+b

*substitute the y and x of the point*

-3=-5(-1)+b

*multiply -5 and -1*

-3=5+b

*subtract 5 on both sides*

-8=b

Now you know b! Let’s put this into our equation

y=mx+b

y=-5x+b

y=-5x-8

This is your answer! Hope this helps comment below for more questions :)

Answer 2

y = -5x -8

Step-by-step explanation:

Find b in equation y = mx + b

Insert numbers to find b

-3 = -5· -1 + b

Step 1: Simplify both sides of the equation.

−3=(−5)(−1)+b

−3=5+b

−3=b+5

Step 2: Flip the equation.

b+5=−3

Step 3: Subtract 5 from both sides.

b+5−5=−3−5

b=−8

Insert into equation

y = -5x - 8