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The output of an economic system​ Q, subject to two​ inputs, such as labor L and capital​ K, is often modeled by the​ Cobb-Douglas production function Q=cL^a K^b. When a+b=​1, the case is called constant returns to scale. Suppose Q=12,200​, a = 1/6​, b= 5/6​, and c=42. Find the rate of change of capital with respect to labor, dK/dL.

User Mouradif
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Answer:

Explanation:

Given

Economic system Q is given by


Q=cL^aK^b

also
a+b=1

if
Q=12,200


a=(1)/(6)


b=(5)/(6)


c=42

substitute these values


12,200=42* (L)^{(1)/(6)}K^{(5)/(6)}


(L)^{(1)/(6)}K^{(5)/(6)}=(12,200)/(42)


K^{(5)/(6)}=\frac{12,200}{42(L)^{(1)/(6)}}


K=((12,200)/(42))^{(6)/(5)}* (1)/(L^(5))

differentiate w.r.t to L to get
(dK)/(dL)


(dK)/(dL)=((12,200)/(42))^{(6)/(5)}* (-5)* L^(-6)


(dK)/(dL)=-5((12,200)/(42))^{(6)/(5)}* (1)/(L^6)


(dK)/(dL)=-(4515.466)/(L^6)

User J Del
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