Question

Solvegbegyeeeeeeeeeeeeeeeeeeeeee

Answer 1

Solution:-

➾
`\sf{x^2-14x = 6}`

➾
`\sf{x^2-14x+30-6 = 0}`

➾
`\sf{x^2-14x+24 = 0}`

By using splitting the middle term method:

➾
`\sf{x^2-12x-2x+24 = 0 }`

➾
`\sf{x(x-12)-2(x-12) = 0}`

➾
`\sf{ (x-12)(x-2) = 0}`

Now, if
`\sf{(x-12) = 0}` then,

➾
`\sf\blue{x = 12}`

And, if
`\sf{(x-2) = 0}` then,

➾
`\sf\blue{ x = 2}`

So, x is equal to either 12 or 2 are the solution of the given equation.