Question

A linear enzyme is formed by four alpha and two beta protein subunits. How manydifferent arrangements are there?

Answer 1

15

Explanation:

We are given that

Number of alpha protein subunits=4

Number of beta protein subunits=2

Total number of protein sub-units=2+4=6

We have to find the number of different arrangements are there.

When r identical letters and y identical letters and total object are n then arrangements are

`(n!)/(r!x!)`

n=6,r=2,x=4

By using the formula

Then, we get

Number of different arrangements =
`(6!)/(2!4!)`

Number of different arrangements=
`(6* 5* 4!)/(2* 1* 4!)`

Number of different arrangements=15

Hence, different arrangements are there= 15