Answer:
18.4 kcal
Step-by-step explanation:
ΔQ = m c Δ t
where ΔQ is heat energy supplied in kcal , m is mass in kg , c is specific heat capacity which is 0.092 kcal / (kg C°) , Δ t = 110-10= 100C°
ΔQ = 2×0.092×100 = 18.4 kcal
heat = 20 Kcal
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