Question

For the reaction shown, find the limiting reactant for each of the initial quantities of reactants 4Cr + 3o2 -> 2Cr2O3 d)14.8 mol Cr; 10.3 mol O2

Answer 1

Answer: O2

Step-by-step explanation:

The balanced chemical equation is:

4 Cr + 3 O2 ---> 2 Cr2O3

4 mol of Cr reacts with 3 mol of O2 to form 2 mol of Cr2O3

For 14.8 mol of Cr, 11.1 mol of O2 is required

But we have 10.3 mol of O2

So, O2 is the limiting reagent