Question

PLEASE HELP ME ASAPPPPPPP!!!!!!!!!!!!!!!!!!!!


ty :D

Answer 1

`y=2x-3`

Skills needed: Point-Slope, Linear Equations

Explanation:

1) We are given
`y=-(1)/(2)x-1`, and we need to find a perpendicular line to this that also passes through the point
`(6,9)`.

- First, we can use the fact that the perpendicular slope is the negative reciprocal of the original slope.

---> This means that
`m*m_p=-1` (original slope x perpendicular slope = -1) This means that
`-(1)/(2)*m_p=-1`

In order to isolate
`m_p`, we multiply both sides by
`-2`

`m_p=-1*-2` -->
`m_p=2`.

The slope of the perpendicular line is 2.

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2) Next, we can use point-slope form.

`y-y_1=m(x-x_1)`

Given
`m` and a coordinate point of
`(x_1,y_1)`.

`m` is the slope

`x_1` is x value of coordinate point

`y_1` is y value of coordinate point

Let's evaluate below:

--->
`y-9=2(x-6)`

distribute on right side:
`y-9=2x-12`

add 6 to both sides:
`y=2x-3`

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`y=2x-3` is your answer! Have a nice day!