Answer:
The area of semicircle is 537.82 cm².
Step-by-step Step-by-step explanation:
Given :
- Diameter of semicircle = 37 cm.
To Find :
Using Formula :
![{\star{\small{\underline{\boxed{\sf{\red{R = (D)/(2)}}}}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/lxbjf3y4fe7ibl07ulh3zyjg75bcw9ixu3.png)
![{\star{\small{\underline{\boxed{\sf{\red{Area = (1)/(2)\pi{r}^(2)}}}}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/cbhg7nk94s4ilkpns90o6pnigdnher004o.png)
Solution :
Here we have given that the diameter of semicircle. So, finding the radius of semicircle by substituting the values in the formula :
![{\dashrightarrow{\pmb{\sf{Radius = (D)/(2)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/eokza8wkcmf628eke4xbxt14ya8e6r47a2.png)
![{\dashrightarrow{\sf{Radius = (37)/(2)}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/edkot18mqka308ildlqsazp5u5km23skvk.png)
![{\dashrightarrow{\sf{Radius = \cancel{(37)/(2)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/hdrgvctck2az77w87karvkl00qqazq1tja.png)
![{\dashrightarrow{\sf{Radius =18.5 \: cm}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/8hjmf2vmnhmepekmldeb52us5ikqtresfu.png)
![{\star{\underline{\boxed{\sf{\pink{Radius =18.5 \: cm}}}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/gfn3u8myfgzsfofx04hmndc4o74j2l8jtr.png)
Hence, the radius of semicircle is 18.5 cm.
![\rule{300}{1.5}](https://img.qammunity.org/2022/formulas/computers-and-technology/college/d65774twaz0valxki6xchlydj44bqzuhee.png)
Now, we know the radius of semicircle. Then, finding the area of semicircle by substituting the values in the formula :
![{\longrightarrow{\pmb{\sf{Area = (1)/(2)\pi{r}^(2)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/k39aeiy1cm2ay2ys2c8ar919tgusvl9bi8.png)
![{\longrightarrow{\sf{Area = (1)/(2) * (22)/(7) * {(18.5)}^(2)}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/38hqgdwphdt45j5ys4l5sp7ika5j1im745.png)
![{\longrightarrow{\sf{Area = \frac{1}{\cancel{2}} * \frac{\cancel{22}}{7} * {(18.5 * 18.5)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/p7w2x7vx3waeekzqt2dyuxj2wwvoeh7ucv.png)
![{\longrightarrow{\sf{Area = (11)/(7) * {(18.5 * 18.5)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/xxbho2rlhc2tj34k2f4zr1j5a17hhu6g3c.png)
![{\longrightarrow{\sf{Area = (11)/(7) * {(342.25)}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/bd12xd50z9foqx1ygcwdbo4nzbaac6o7av.png)
![{\longrightarrow{\sf{Area = (11)/(7) * 342.25}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/kjoiy2x5rthscsrz0kl7jpozy2rp2mzfq8.png)
![{\longrightarrow{\sf{Area = (11 * 342.25)/(7)}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/4e8iaqphnj1p50s6q907td2pniagdqj2ch.png)
![{\longrightarrow{\sf{Area = (3764.75)/(7)}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/febznd22xvvs3x5la3s50kvgjsnvm7h9ng.png)
![{\longrightarrow{\sf{Area \approx 537.82 \: {cm}^(2)}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/1q4vyqrzmjbw432dopdmq4pbd8azpb6d6m.png)
![{\star{\underline{\boxed{\sf{\pink{Area \approx 537.82 \: {cm}^(2)}}}}}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/o39q930sea5jaxfgej3jn30ghz6cqq778q.png)
Hence, the area of semicircle is 537.82 cm².
![\rule{300}{1.5}](https://img.qammunity.org/2022/formulas/computers-and-technology/college/d65774twaz0valxki6xchlydj44bqzuhee.png)