Question

A car in dynamic equilibrium is acted upon by the following forces:

force due to gravity = -9,000 newtons
force due to friction = -250 newtons
forward force exerted by engine = 250 newtons
What is the value of the force exerted by the ground on the car?
-9,000 newtons
+9,000 newtons
+250 newtons
-250 newtons

Answer 1

9000 N.

We know that the car is in equilibrium, so all the forces resultants must be equal to 0. Along the y-axis we have the weight and the force exerted by the ground, that have to be equal to 0 as well... so -9000 + x - 0

x = 9000N