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Find the volume of 8 gram of oxygen gas​

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Atomic mass of Oxygen= 16g
So 16 g of oxygen contains = N atoms of Oxygen.
{ N= Avagadro number= 6.022 x 10²³}
So 8 g of Oxygen contains= N/2 ATOMS of Oxygen
=6.022x10²³/2
= 3.011 x10²³ atoms

Number of moles of O
2

=
32
8

=
4
1

=0.25

Volume of 1 mol of O
2

at STP =22.4 L

∴ Volume of 0.25 mol of O
2

at STP =22.4×0.25=5.6 L
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