Explanation:
a lot of typos in the problem description.
if I understand correctly, the line contains the point (5, 10) and has a slope of 1.
and we need to give the line equation in slope-intercept form.
that means it has to look like
y = ax + b
a is the slope and b is the y-intercept (hence the name of the form).
we know a = 1.
we can use use the point-slope form to start and then transform it into the slope-intercept form.
point-slope means
y - y1 = a(x - x1)
a is again the slope, and (x1, y1) is a point on the line.
so,
y - 10 = 1(x - 5) = x - 5
now we transform it (adding 10 on both sides)
y = x + 5
and that's it.