Question

20 PIONTS PLZ HELP

What mass of calcium chloride is needed to make 330.0 mL of 0.125 M
solution?

Answer 1

4.58g

Step-by-step explanation:

1.) What is the molar mass of CaCI2?

= 110.98 g/mol

2.) Find the mols

`conc = (mol)/(volume(l))`

conc × volume= mol

0.125 M x 0.33 L = 0.04125mol ( 330mL was converted to "L" by dividing 330 by 1000)

3.) The mass(g)

g= mol x atomic weight

g= 110.98g/mol × 0.04125

= 4.58 g

# NOTE M = mol/L