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What is the area of a triangle whose vertices are R(-4, 2). S(1, 2), and T(-5, - 4) ?

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User Sysyphus
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1 Answer

4 votes

Answer:

-15 sq. units

Explanation:

To solve this, we'll use the formula.

Coordinate Geometry formula for a triangle:


(1)/(2) [(x_1 (y_2 - y_3) + x_2 (y_3 - y_1) + x_3(y_1 - y_2)]

R(−4, 2), S(1, 2), and T(−5, −4) as the vertices of △RST


x_1 = - 4, y_1 = 2


x_2 = 1, y_2 = 2


x_3 = - 5, y_3 = - 4

Plugin the values; solve


(1)/(2) [-4 (2 - (-4)) + 1 (- 4 - 2) + (-5) (2 - 2)]


=(1)/(2) [-24 - 6 - 0]


= (1)/(2) [-30]


= (-30)/(2)


= -15

Therefore, the area of the triangle is -15 sq. units.

What is the area of a triangle whose vertices are R(-4, 2). S(1, 2), and T(-5, - 4) ? Enter-example-1
User Masoud Mohammadi
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