Question

Solve the equations below exactly. Give your answers in radians, and find all

possible values for t in the interval 0 (less than or equal to ) t (less than or equal to) 2 pi
If there is more than one
answer, enter your solutions in a comma separated list.

(a) sin (t) = - square root of 3 divide by 2
when t=

(b) cos (t) = 1/2
when t=

Answer 1

See below (along with unit circle attached)

Explanation:

`sin(t)=-(√(3))/(2)`

`t=(4\pi)/(3),(5\pi)/(3)`

`cos(t)=(1)/(2)`

`t=(\pi)/(3),(5\pi)/(3)`

It really helps to use the unit circle! I've attached it below for your convenience. Keep in mind that a point on the unit circle is defined by
`(cos(\theta),sin(\theta))` where
`\theta` is measured in radians.