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What is an equation of a line that passes through the point

(0,3) and is perpendicular to the line whose equation is
y = 2x - 1?
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What is an equation of a line that passes through the point (0,3) and is perpendicular-example-1
User CDJB
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1 Answer

5 votes

Answer: y = -(1/2)x + 3

Explanation:

y = 2x - 1

This is in the format of y=mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the reference line. The slope of this reference line is 2, so the slope of a perpendicular kline will be -(1/2).

This yields the equation y = -(1/2)x + b

To find the value of b, we can use the given point, (0,3) and use these values of x and y to solve for b:

y = -(1/2)x + b

3 = -(1/2)(0) + b

b = 3

The equation of a line perpendicular to y = 2x - 1 and goes through point (0,3) is:

y = -(1/2)x + 3

What is an equation of a line that passes through the point (0,3) and is perpendicular-example-1
User Qiong
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8.0k points