439,316 views
12 votes
12 votes
There are many four-digit positive integers in which the product of the digits is equal to $5!$. What is the sum of the largest and smallest such four-digit numbers

User Elcomendante
by
3.0k points

2 Answers

21 votes
21 votes

Answer:

7

Explanation:

5! = 1×2×3×4×5

they want 4 numbers that = 120

so

2x3x4x5 = 120

2 + 5 = 7

User Randomafk
by
2.4k points
24 votes
24 votes

Answer:

9889

Explanation:

User Thomas Arildsen
by
2.9k points