Solve the equation by using quadratic formula . Show your work! Answer maybe in radical or decimal form . 2x^2 + 4x – 5 = 0

asked Mar 28, 2022 202k views

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Solve the equation by using quadratic formula . Show your work! Answer maybe in radical or decimal form .

2x^2 + 4x – 5 = 0

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Answer:

$x_1=(-2+√(14))/(2)\approx 0.871,x_2=(-2-√(14))/(2)\approx-2.871$

Explanation:

2x^2+4x-5=0

$x=(-b\pm√(b^2-4ac))/(2a)$

$x=(-4\pm√(4^2-4(2)(-5)))/(2(2))$

$x=(-4\pm√(16+40))/(4)$

$x=(-4\pm√(56))/(4)$

$x=(-4\pm2√(14))/(4)$

$x=(-2\pm√(14))/(2)$

$x_1=(-2+√(14))/(2)\approx 0.871,x_2=(-2-√(14))/(2)\approx-2.871$

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