Question

Find the value (6° -2°) x (6° +2°)

Answer 1

0

Explanation:

using the identity

`a^(0)` = 1 , then

(
`6^(0)` -
`2^(0)` ) × (
`6^(0)` +
`2^(0)` )

= (1 - 1) × (1 + 1)

= 0 × 2

= 0

Answer 2

The value of any number or variable raise to 0 is 1
a^0 = 1
6^0-2^0 = 1-1
= 0
(6^0 -2^0)*(6^0+2^0) = 0*(1+1)
= 0