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What is the angle, in degrees, when the coordinate is (-√(2) /2), √(2) /2) ? Pls help thanks
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4 votes
What is the angle, in degrees, when the coordinate is
(-√(2) /2), √(2) /2) ? Pls help thanks

User CafeHey
by
5.6k points

1 Answer

6 votes

Answer:

135°

Explanation:

seg AB=seg OB

tan ∠AOB = 1

∠AOB = 45°

∠AOC = 135°

What is the angle, in degrees, when the coordinate is (-√(2) /2), √(2) /2) ? Pls help-example-1
User Gordolio
by
5.6k points
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