Question

5.00-kg particle starts from the origin at time zero. Its velocity as a function of time is given by v =6t^2 i + 2t j where v is in meters per second and t is in seconds. (a) Find its position as a function of time. (b) Describe its motion qualitatively. Find (c) its acceleration as a function of time, (d) the net force exerted on the particle as a function of time, (e) the net torque about the origin exerted on the particle as a function of time, (f) the angular momentum of the particle as a function of time, (g) the kinetic energy of the particle as a function of time, and (h) the power injected into the system of the particle as a function of time.

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Answer:A 5.00 kg particle starts from the origin at the time zero. its velocity as function of time is v=6t^2i+2tj where v in meters per second and t ...

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(a) The position as function of time is x(t)=2t3i^+t2j^.x(t)=2t^3\hat\textbf i+t^2\hat\textbf j.x(t)=2t3i^+t2j^​. (b) Describe the motion qualitatively. ...

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