Question

Write an equation of the line passing through point P(4,3) that is parallel to the line y = 12(x+4).

y= ?

Answer 1

Explanation:

y = 12(x+4)

can be re written as

(y - 0) = 12(x + 4)

Which now is in the slope-point form where slope is 12 and the point is (-4, 0)

To get an equation for a parallel line through a different point. Just change the point to (4, 3)

(y - 3) = 12(x - 4)

This equation can be converted to the slope intercept form by expanding and combining terms

y - 3 = 12x - 48

y = 12x - 45

Answer 2

y = 12x - 45

Explanation:

y = 12(x + 4)

y = 12x + 4 Slope = 12. Two lines are parallel if their slopes are the same.

Use the slope and the given point (4,3) and substitute into the slope-intercept form and solve for b

y = mx + b

3 = 12(4) + b

3 = 48 + b

-45 = b

y = 12x - 45