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A 65kg swimmer pushes off the pool wall and accelerates at 6m/s2. The friction experienced by the swimmer is 100n. What is the magnitude of the force that the swimmer applies on the wall?.

User Johnny Bou
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1 Answer

4 votes

Answer:

490 N

Step-by-step explanation:

Fnet = ma

= 65*6

= 390 N

Net force is applied force (Fapp) and friction force (Ff) in the opposite direction.

Fnet= Fapp - Ff

390=x-100

x=490N

User Birdmw
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4.7k points