Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/college/ym0yri6u0ig2pz5daeb7b02dcow5nipuym.png)
Explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] * \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/college/ug5qbayuqwu5xqfxwgoc6bc3mx4z6b9mh3.png)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/college/ym0yri6u0ig2pz5daeb7b02dcow5nipuym.png)