Question

determine the force of gravitational attraction between a 4,000 kg elephant that is 10 meters away from a 180 kg lion

Answer 1

`F_(g) = 4.8` ×
`10^(-7)`
`N`

Step-by-step explanation:

The law of gravitational attraction states :

`F_(g) = G(Mm)/(R^(2) )`

G is the gravitational constant
`(6.67` ×
`10^(-11)`
`)`

M is the larger mass (kg)

m is the smaller mass (kg)

R is the distance separating the two objects (
`m^(2)`)

∴
`F_(g) =`
`(6.67` ×
`10^(-11)`
`)`
`(4000)(180)/(10)^(2)`

`F_(g) = 4.8` ×
`10^(-7)`
`N` is the gravitational force between the elephant and the lion.