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How many grams of zinc chloride could be formed from the reaction of 3. 57g zinc with excess hcl?.

User Burnell
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1 Answer

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Zn+2HCl = ZnCl2 + H2
Zn= ZnCl2
65.38g Zn= 136.315 g ZnCl2
1g Zn = 136.315/65.38 g ZnCl2
3.57 g Zn = (136.315/ 65.38) × 3.57 g of ZnCl2
3.57g Zn = 7.443g ZnCl2
User Lonare
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