Question

4) The length of a rectangle is double its width. Its perimeter is 33cm. How long is its

width?

Answer 1

The width of the rectangle is 5.5 cm, which is found by using the perimeter formula and the fact that the length is double the width.

Step-by-step explanation:

The student is attempting to find the width of a rectangle given that the length is double the width and the perimeter is 33 cm. To solve this problem, we can use the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width. The problem states that l = 2w, so we can substitute this into our perimeter formula to get P = 2(2w) + 2w = 6w. Since we know the perimeter is 33 cm, we can set up the equation 33 = 6w and solve for w.

Dividing both sides of the equation by 6, we find that w = 33 / 6, which simplifies to w = 5.5. Therefore, the width of the rectangle is 5.5 cm.

Answer 2

5.5 cm

Step-by-step explanation:

Let x be the width of the rectangle.

Since the length is double the width, the length would be 2x.

x can be found by solving the perimeter equation. The perimeter of the rectangle can be found by the equation:

`p = 2(l + w)`

`33 = 2(2x + x)`

`33 / 2 = (2x + x)`

`16.5 = 3x`

`16.5 / 3 = x`

`5.5 = x`

Therefore, the width of the rectangle is 5.5 cm.