Question

How do I do i’m not sure

Answer 1

`(a)\\\\m=6.1* 10^(-5),~~ t=1.7 * 10^(-6) \\G = \sqrt{(m)/(t^2)} = \sqrt{(6.1* 10^(-5))/(\left(1.7 * 10^(-6)\right)^2) } ~=4590\\\\\\(b)\\\\m=6.1* 10^(-5)(1+ 8\%) = 6.1* 10^(-5)(1+0.08) = 0.0000648\\\\t=1.7* 10^(-6)(1+ 5\%)= 1.7* 10^(-6)(1+0.05) =0.000001785\\\\\\G=\sqrt{(m)/(t^2)} = \sqrt{(0.0000648)/((0.000001785)^2)}=4510`