Answer:
it is 1 / square root of the change in distance
Step-by-step explanation:
since the equation of the gravitational force is
![F=G{(m_1m_2)/(r^2)}](https://img.qammunity.org/2022/formulas/physics/high-school/l4kxxp9krt72p228p1nc8y9w29ktgfj8pp.png)
then F and r are inversely related, by the equation
![F \alpha (1)/(r^2)](https://img.qammunity.org/2022/formulas/physics/high-school/4rhzljxldz8t6zrdqhereln4wu8jx0pxw5.png)
this means when F is multiplied by 2 then r^2 is multiplied by half
so when r is multiples by half we first square the number (0.5) ^ 2 = 0.25
so
![F \alpha (1)/((0.25)r^2)](https://img.qammunity.org/2022/formulas/physics/high-school/kwm3rmtalz0cd1c6lkz9eq47vjjnptvahc.png)
which means F is multiples by 1/0.25 or 4 when the radius is halfed