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2logx= log 16 + log 4 find the value of x​

1 Answer

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Explanation:

the rules of logarithm.

log(a×b) = log(a) + log(b)

log(a^b) = b×log(a)

2×log(x) = log(16) + log(4)

now, using the above knowledge :

log(x²) = log(16×4)

=>

x² = 16×4 = 64

x = ±8

and since a logarithm of a negative number is undefined the only plausible solution is

x = 8

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