Question

Jack has a bag of jellybeans. There are 6 green, 4 blue, 5 red, and 1 yellow jellybean. If Jack picks two jellybeans replacing the first, then find the probability of each.

P(blue and red) =
P(yellow and green) =
P(blue or yellow, green) =
P(green and blue and red) =​

Answer 1

Answer: See below for totals:

Explanation:

P(blue and red) =
`(4)/(16) *(5)/(16) = (20)/(256) =(5)/(64)`

P(yellow and green) =
`(1)/(16) *(6)/(16) =(6)/(256) = (3)/(128)`

P(blue or yellow, green) =
`(5)/(16) *(6)/(16) = (30)/(256) =(15)/(128)`

P(green and blue and red) =​
`(6)/(16) *(4)/(16) *(5)/(16) =(120)/(4096) =(15)/(512)`

Hope this helps!