Question

a A force of 100N is required to stretch a string that obeys Hooks law by 50cm. What is the work done in stretching the spring?​

Answer 1

`workdone \: in \: stretching \: a \: spring \: = (1)/(2)ke {}^(2) \\ workdone = (1)/(2)fe \\ beause \: f = ke \\ f = 1000 \: \: x = 50cm \: = 0.5m \\ w = (1)/(2) (100)(0 .5) { }^(2) \\w = 12.5 \: newtonpermetre`