Question

A company makes a beverage that must have 12% real-juice content. How many gallons of beverage with 9% real-juice content must be mixed with 3000 gallons of beverage with 15% real-juice content to achieve the desired 12% real-juice content?

Answer 1

3000

Explanation:

Answer 2

Answer:3000

first lets change this problem into an equation...

0.09*x+0.15*3000=0.12(x+3000)

Step 1: Simplify both sides of the equation.

0.09x+(0.15)(3000)=0.12(x+3000)

0.09x+(0.15)(3000)=(0.12)(x)+(0.12)(3000)

0.09x+450=0.12x+360

Step 2: Subtract 0.12x from both sides.

0.09x+450−0.12x=0.12x+360−0.12x

−0.03x+450=360

Step 3: Subtract 450 from both sides.

−0.03x+450−450=360−450

−0.03x=−90

Step 4: Divide both sides by -0.03.

-0.03x/-0.03=-90/0.03

x=3000