29.2k views
1 vote
NO LINKS!!!!

Consider the following sequence 4, 8, . . .
a. Assuming the sequence is arithmetic:
i. Write the next four terms
ii. What is the generator?
iii. Write a formula for t(n).
iv. Create a table and graph your sequence.

b. Assuming the sequence is geometric:
i. Write the next four terms

ii. What is the generator?

iii. Write a formula for t(n).

iv. Create a table and graph your sequence

User Yari
by
3.6k points

1 Answer

4 votes

9514 1404 393

Answer:

a. 12, 16, 20, 24; t(n)=4n

b. 16, 32, 64, 128; t(n)=2·2^n

Explanation:

a. The difference of the given terms is 8-4=4, so the arithmetic sequence has a first term of 4 and a common difference of 4. The general term has the formula ...

t(n) = t(1) +d(n -1)

t(n) = 4 +4(n -1) . . . . . with t(1) and d filled in

t(n) = 4n . . . . . . . . . . simplified

This formula can be considered to be the generator of the sequence. For values of n from 3 to 6, the next four terms are ...

t(3) = 12; t(4) =16; t(5) = 20, t(6) = 24

A table and graph are shown in the first attachment.

__

b. The ratio of the given terms is 8/4 = 2, so the geometric sequence has a first term of 4 and a common ratio of 2. The general term has the formula ...

t(n) = t(1)·r^(n-1)

t(n) = 4·2^(n-1) . . . . . . . with t(1) and r filled in

t(n) = 2·2^n . . . . . . . . simplified

This formula can be considered to be the generator of the sequence. For values of n from 3 to 6, the next four terms are ...

t(3) = 16; t(4) = 32; t(5) = 64; t(6) = 128

A table and graph are shown in the second attachment.

NO LINKS!!!! Consider the following sequence 4, 8, . . . a. Assuming the sequence-example-1
NO LINKS!!!! Consider the following sequence 4, 8, . . . a. Assuming the sequence-example-2
User Patrick Lorio
by
3.2k points