Answer:
The distance traveled before takeoff is 1720 m
Step-by-step explanation:
Given:
a = + 3.2 m/s²
t = 32.8 s
Vᵢ = 0 m/s
To Find:
d = ?
Now,
d = Vᵢ × t + 0.5 × a × t²
d = (0 m/s) × (32.8 s) + 0.5 × (3.20 m/s²) × (32.8 s)²
d = 1720 m
Thus, The distance traveled before takeoff is 1720 m
-TheUnknownScientist 72