Answer:
Betty is 15.
Mike is 5.
Explanation:
We can let Betty's age be b and Mike's age be m.
Since Betty's age is 3 times of Mike, then
![b=3m](https://img.qammunity.org/2022/formulas/mathematics/high-school/3esd8guc23cxtf1aqmlq4u4orryqmhv2j9.png)
In 5 years, the age of Betty and Mike would be
and
respectively.
Since Betty is 2 times as old as Mike then, then
.
We know that
, so we can substitute that:
![3m+5=2(m+5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3mpzqk4d0yc49l2ffhg50r6lmufig1e32o.png)
Expand:
Subtract 5 from both sides:
![3m+5-5=2m+10-5](https://img.qammunity.org/2022/formulas/mathematics/high-school/bbq842y634hfgnv95wfbsigdbi5mgazdh2.png)
![3m=2m+5](https://img.qammunity.org/2022/formulas/mathematics/high-school/uuh1osvsqfv963m6e0k7l5whqvdysmx0y8.png)
Subtract 2m from both sides:
![3m-2m=2m+5-2m](https://img.qammunity.org/2022/formulas/mathematics/high-school/jxsms7aub5o125hz6ivc0m5qvojb7ys3j0.png)
.
Mike is 5 years old.
Since Betty is 3 times as old as Mike, Betty's age is
![5*3=15](https://img.qammunity.org/2022/formulas/mathematics/high-school/jpzva4piktulysexwxb37z7zls1s03qox4.png)