Answer:
Q9: C.
Since each smaller line counts as 1/5, you can simply start from the point 1 and count 3 times to reach D.

Since you started at 1, you can add

Q10: B
We can subtract/ignore 3 from all of them to make things simpler.
Now, we need to find the lowest value to greatest from:

In order to compare these, we make the denominators the same (in this case: 16)



Since 7 is the smallest value, followed by 8 and lastly 10,
the smallest to greatest in order would be
(B)
11: C
If you look at both
and
, they are not directly above one another. Hence, they are not equal.