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Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244. URGENT

User Linkdd
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1 Answer

4 votes

Answer:

-39+5(-41)=244

Explanation:

Consider 3 consecutive integers: (smallest) x, x+1 and x+2 (largest)

Five times the smallest means 5x

Sum of the largest and five times the smallest means x+2+5x

This sum is -244 means x+2+5x=-244

Solve this equation

x+2+5x=-244

6x+2=-244

6x=-244-2

6x=-246

x=-41

So, smallest number is -41, second is -40 and largest is -39

= -39+5(-41)=244

Hope this helps, have a nice day/night! :D

User Ragoler
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