Answer:
0.8569 kgm of water
Step-by-step explanation:
Deanne takes a pot or water off the stove to let it cool down. The water was
initially at a temperature of 93.1°c and cooled down to a temperature of 22.3°c. The water released 253,592 J of heat into the air as it cooled.
How many kilograms of water were in the pot?
a calorie is the amount of heat neede to raise 1 gm of water 1 degree C.
253, 592 joule given off
this in calories is 253492 /4.18 = 60668 calories
the temperature change was 93.1 -22.3 = 70.8 degrees in C
so 60668/70.8 =856.9 gm of water or 856.9/1000 =0.8569 kgm of water