Answer:
x>2 or (2,∞)
Explanation:
if x≤2, 3*|2-x| = 3*(2-x) = 6-3x
3*|2-x| +3x-6 = (6-3x) + 3x-6 = 0 ... f(x) -> ∞ denominator = 0
if x>2, 3*|2-x| = 3*-(2-x) = -6+3x
3*|2-x| +3x-6 = (-6+3x) + 3x-6 = 6x - 12 >0
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