Question

Write an equation that passes through (2,4) is parallel to the line 3x-2y=-10

Answer 1

y = 3x/2 + 3

Explanation:

First let's solve for y in the given equation

Subtract 3x from both sides

3x - 2y = -10

- 3x - 3x

-2y = -3x - 10

Divde both sides by -2

-2y/-2 = (-3x - 10)/-2

y = 3x/2 + 5

The slop of the parallel equation will have to be 3/2

y = 3x/2 + b

Plug in the given coordinates

4 = 3(2)/2 + b

4 = 1 + b

Subtract 1 from both sides

4 = 1 + b

- 1. - 1

b = 3

y = 3x/2 + 3