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How do you solve for n and what is the rule?

How do you solve for n and what is the rule?-example-1
User Luigibertaco
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2 Answers

27 votes
27 votes

Answer:

Looking at the first two given ordered pairs (3, 5) and (4, 7), it appears that for every increase of 1 unit of x, there is an increase of 2 units of y.

Let's check by writing the next ordered pairs using this rule:

(5, 9) (6, 11) (7, 13) (8, 15)

As the the ordered pair (8, 15) is in the table, then we can confirm that this is the rule.

Writing the rule as an equation:

y = 2x - 1

Therefore, n = 6

User Kalium
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15 votes
15 votes

Answer:

y = 2x - 1

n = 6

Explanation:

Hello!

This is an arithmetic sequence.

An Arithmetic sequence, also known as an arithmetic progression, is a string of numbers that follow a pattern where the difference between two terms is always the same (constant).

An Arithmetic sequence is modeled by the explicit function:
\bold{t(n) = (CD)n + t(0)}

  • t(n) = output (y - value)
  • CD = common difference (slope)
  • n = input ( x-value)
  • t(0) = starting value (y-intercept)

Let's go step by step to solve these equations:

Step 1: Common Difference

The common difference of a sequence is similar to the slope of a line. The slope formula is given as
\bold{(y_2 - y_1)/(x_2-x_1)}.

We can input values of x and y to find the common difference


  • (y_2 - y_1)/(x_2-x_1)

  • (7 - 5)/(4 - 3)

  • \frac21 = 2

We have the CD, 2!

Step 2: Starting Value

The starting value can be shown as the y-intercept of the line or the origin point of the sequence.

To find the starting value or t(0), we can input an x and y value for "n" and "t(n)"

  • t(n) = (CD)n + t(0)
  • 5 = 2(3) + t(0)
  • 5 = 6 + t(0)
  • -1 = t(0)

We know have the starting value, -1!

Step 3: The Equation

We now have all the values for our equation. let's bring our attention back to the input and output variables. Since we know that "t(n)" is the same as "y" and "n" is the same as "x", we can plug that instead of t(n) and n.

  • t(n) = (CD)n + t(0)
  • t(n) = 2n -1
  • y = 2x - 1

Solve for n:

With our equation, we can plug in 11 as the output and solve for n.

  • y = 2x - 1
  • 11 = 2x - 1
  • 12 = 2x
  • 6 = x

n = 6

_______________________________________________________

Another way to solve this is to find the Recursive Equation

The Recursive Equation is only meant to find the next term, it doesn't do so well in finding the terms in the long run.

The basic form of a recursive equation is t(n + 1) = t(n) + (CD); where t(0) is ____

I'm not going to go in-depth with this, but you can see the values that we solved above can be implemented here.

Our recursive equation is t(n + 1) = t(n) + 2; where t(0) is -1

The port outside of the semi-colon represents where the sequence starts. If only t(n+1) = t(n) + 2 is given, we could start at 5, and go as 5, 7, 9...etc.

We would start by finding t(1) by doing:

  • t(0 + 1) = t(0) + 2; where t(0) = -1
  • t(1) = -1 + 2
  • t(1) = 1

We can confirm this using our explicit rule: y = 2x - 1

  • y = 2(1) - 1
  • y = 2 - 1
  • y = 1


User Grimtron
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3.6k points