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the horizontal component of a net force is 68 newtons and the angle made by the net force with the horizontal is 19., what is the value of the net force?​

1 Answer

5 votes

71.9 N

Step-by-step explanation:


F_h = Fcos(19°) \Rightarrow F = (F_h)/(cos(19°))


F = (F_h)/(cos(19°)) = \frac{68\:\text{N}}{cos(19°)}


\:\:\:\:= 71.9\:\text{N}

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