9514 1404 393
Answer:
f(x) = x^6 -10x^5 +89x^4
Explanation:
For a given zero p with multiplicity n, one of the factors of the polynomial will be (x -p)^n. If the polynomial has real coefficients, then the complex zeros come in conjugate pairs.
The factored form of your polynomial is ...
f(x) = (x -(5 -8i))(x -(5 +8i))(x -0)^4
f(x) = ((x -5)^2 -(8i)^2)(x^4) = (x^2 -10x +89)(x^4)
f(x) = x^6 -10x^5 +89x^4