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new york city is the most expensive city in the united states for lodging the man hotel room rate is $204 per night . assume the room rates are normally distributed with a standard deviation of $55. what is the probability a room cost $225 or more a night

User Minhee
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64% (225-204)/55 = .38 …. Z table = .35971 (1-.35971) = .64 = 64%. I’m about 90% confident that’s the right answer
User Orifjon
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