10.6k views
0 votes
Write an equation of the line that passes through (0,4) and (1,2).

User Aknon
by
3.3k points

1 Answer

3 votes

Answer:

Explanation:

Let's assume this is a straight line, so we can use the basic form of a straight line equation: y=mx+b, where m is the slope and b is the y-intercept (the value of y when x is zero).

The slope is the rate of change of the line, and can be calculated by dividing the change in y by the change in x between any two points. Here: (0,4) and (1,2)

The change in y is known as the "Rise." Going from (0,4) to (1,2), we have a change of -2:

(2 - 4) = -2 This is the Rise (Final minus the initial values)

X changes by 1 (1-0) = 1 (Final minus the initial values)

Rise/Run = -2/1 or -2

The slope, m, is -2. Values of y decrease as x increases.

The equation becomes y = -2x+b

The value of b must be such it forces the line to go between the two points. We can calculate b by i=using one of the two points in out unfinished equation and solve for b. I'll pick (1,2).

y = -2x+b

2 = -2*(1) + b

b = 4

The equation becomes y=-2x+4

Write an equation of the line that passes through (0,4) and (1,2).-example-1
User Alexwhan
by
4.0k points