Answer:
Explanation:

Cross multiply,
3x = 2y ------------(I)

y = z --------------(II)
Plugin y =z in (I)
3x = 2z
3x/2 = z ----------------(III)
x + 2y - z = 10
From (I) and (III)

Divide both sides by 5
x = 20/5
x = 4
Plugin x = 4 in (I)
3*4=2y
12 = 2y
2y = 12
y = 12/2
y = 6
z = y
z = 6