Question

How much would $300 invested at 9% interest compounded continuously be

worth after 3 years? Round your answer to the nearest cent.
A(t)=P•e^rt
O A. $392.98
O B. $364.18
O C. $306.11
O D. $381.00

Answer 1

Use the formula A = Pe^(r*t).

A = $300*e^(0.09*3) = $392.99.

Explanation: