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Find the stationary points of the function f(x)=2x³-15x²+36x+6

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Answer:

2,3

Explanation:

the derivative is in the image above

stationary points = zeros of the derivative

derivative = 36-(30x)+(6x^2)

the zeros are x= 2 and x=3

stationary points occur at x= 2 and x=3

Find the stationary points of the function f(x)=2x³-15x²+36x+6-example-1
User MStoner
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